sql 查詢記錄數(shù)結(jié)果集某個區(qū)間內(nèi)記錄
發(fā)布日期:2022-01-09 14:47 | 文章來源:CSDN
方法一: 先正查,再反查
select top 10 * from (select top 30 * from tablename order by id asc) A order by id desc 方法二: 使用left join
select top 10 A.* from tablename A
left outer join (select top 20 * from tablename order by id asc) B
on A.id = B.id
where B.id is null
order by A.id asc 方法三: 使用not exists
select top 10 * from tablename A
where id not exists
(select top 20 * from tablename B on A.id = B.id) 方法四: 使用not in
select top 10 * from tablename
where id not in
(select top 20 id from tablename order by id asc)
order by id asc 方法五: 使用rank()
select id from
(select rank() over(order by id asc) rk, id from tablename) T
where rk between 20 and 30 中第五種方法看上去好像沒有問題,查了下文檔,當(dāng)over()用于rank/row_number時,整型列不能描述一個列,所以會產(chǎn)生非預(yù)期的效果. 待考慮下,有什么辦法可以修改為想要的結(jié)果.
select top 10 * from (select top 30 * from tablename order by id asc) A order by id desc 方法二: 使用left join
select top 10 A.* from tablename A
left outer join (select top 20 * from tablename order by id asc) B
on A.id = B.id
where B.id is null
order by A.id asc 方法三: 使用not exists
select top 10 * from tablename A
where id not exists
(select top 20 * from tablename B on A.id = B.id) 方法四: 使用not in
select top 10 * from tablename
where id not in
(select top 20 id from tablename order by id asc)
order by id asc 方法五: 使用rank()
select id from
(select rank() over(order by id asc) rk, id from tablename) T
where rk between 20 and 30 中第五種方法看上去好像沒有問題,查了下文檔,當(dāng)over()用于rank/row_number時,整型列不能描述一個列,所以會產(chǎn)生非預(yù)期的效果. 待考慮下,有什么辦法可以修改為想要的結(jié)果.
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